jawaban fiska ~

1. Diket: gas O2 (Mr = 32 g/mol = 32 x 10^-3 kg/mol)
V = 1 L = 10^-3 m³
n = 2 mol
v rms = 200 m/s
R = 8,31 J/mol.K
Dit: P
Jwb:
v = √(3 R T/Mr)
v² = 3 R T/Mr
200² = 3 x 8,31 x T/(32 x 10^-3)
40000 = 779,0625 T
T = 51 K

P V = n R T
P x 10^-3 = 2 x 8,31 x 51
P = 847620 N/m²
P = 8,4762 x 10^5 N/m²
atau
P ≈ 8,5 atm


2. Diket: gas A dan gas B
ρA = 10 ρB
vA = vB

Dit: PA : PB
Jwb:
v = √(3 N k T/M) 
v = √(3 P/ρ)
→ kedua ruas dikuadratkan
v² = 3P/ρ

vA = vB
vA² = vB²
3PA/ρA = 3PB/ρB
PA/(10 ρB) = PB/ρB
PA/10 = PB/1
PA = 10 PB
atau
PA : PB = 10 : 1